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title: Coderbyte #2: Bracket Combinations Challenge in Python
description: A beginner-friendly walkthrough of the Bracket Combinations challenge from Coderbyte, solved in Python using backtracking. The post explains how to generate...
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# Coderbyte #2: Bracket Combinations Challenge in Python

**[Medium](https://daily.dev/sources/medium_js)** · 4 min read · 1 upvotes · 0 comments

## Summary

A beginner-friendly walkthrough of the Bracket Combinations challenge from Coderbyte, solved in Python using backtracking. The post explains how to generate all valid parentheses combinations for a given number of pairs by applying two simple rules: only add an opening bracket if you haven't exceeded the limit, and only add a closing bracket if there are more openers than closers. The backtracking approach builds combinations incrementally, avoiding brute-force enumeration.

## Full article

daily.dev links to this article rather than hosting it. Read it at the original source: <https://medium.com/@shruti.mandaokar/coderbyte-2-bracket-combinations-challenge-in-python-43ab4aad2213>

## Questions this post answers

### How do you generate all valid combinations of balanced parentheses using backtracking in Python?

Use recursion with two counters tracking open and close bracket usage. Add an opening bracket whenever the open count is less than num, and add a closing bracket only when the close count is less than the open count so far. Recurse on each valid choice, passing the updated string and counters, until the string reaches full length, producing only well-formed combinations like ((())) or ()()().

_Developers practicing recursion patterns like this one often keep reference solutions handy through daily.dev._

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---

Tags: [#python](https://daily.dev/tags/python), [#algorithms](https://daily.dev/tags/algorithms), [#interview-questions](https://daily.dev/tags/interview-questions), [#recursion](https://daily.dev/tags/recursion)

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